Hi ,


Figured it out myself I had to write a little thingy others might like it

Qx = number of selections in top row
Qy = number of selections in second row

TempQcost = 0
QCost = 0

For QCalc = 1 To Qx

TempQcost = 1 * Qy - 1
QCost = QCost + TempQcost
Qy = Qy - 1

Next QCalc

That is it, once the calculation comes out of the loop the Quinella (QCost) is calculated correctly I think.

I also feel quite smart again

Michal