Barry,

According to your data, Red will come up 72% of the time which means black must come up 28%(you said to ignore the green). You are calling black an "out" so assuming the spins are independant, any spin has a 28% or .28 chance of being an out. To work out the chance of x number of consequtive outs we multiply .28 x-times. So 3 outs in a row would be .28x.28x.28=.022 or a 2.2% chance that in any 3 spins a red does not appear. The probability of going 10 spins in a row without a red would be .28^10=.000003 which equates to 3 times out of a million you would expect to go 10 spins without a red.

Hope this helps.

PS Where can I find this roulette wheel?